When I see my daughter sleeping soundly, I think sometime what dream she is seeing. If I can see her dream on real time, it may be not the dream as it is. How does someone observe an object observed by another person? It is the 'Lorentz transformation' that replies to this question.
Three kinds of observers appear in this book. First, there is an observer who observes only stationary objects. We will call him/her 'the 0th observer.' Next, there is an observer who observes objects being observed by many 0th observers who keep linear uniform motion in various directions at various speeds. We will call him/her 'the 1st observer.' Last, there is an observer on linear uniform motion who observes objects being observed by the 1st observer. We will call him/her 'the 2nd observer.'
In this chapter, we study how an object observed by the 0th observer is observed by the 1st observer. For this purpose, we use the ' Lorentz transformation ' under the condition of
;

of
stands for the infinitesimal intervals.
Now let us think how infinitesimal intervals of distance (
) and time (
) are converted with the 'Lorentz transformation.'
Let (
,
) and (
,
) be coordinates of the 0th observer and coordinates of the 1st observer, respectively.
Then,
and
are expressed as follows :
![]()

![]()
(Equality 5-1)
Owing to (Equality 5-1) we obtain the following equality :
( d r ) 2 - ( d t ) 2 = ( d r 0 ) 2 - ( d t 0 ) 2
![]()
(Equality 5-2)
Now, let us think about a statinary object in an inertial frame of reference moving at a speed of
. In other words, let us think about an object traveling with linear uniform motion at a speed of
. In another words, let us think about a stationary object for the 0th observer moving at a speed of
relative to the 1st observer from the stand of view of the 1st observer .
A stationary object observed by the 0th observer keeps always
.
When
, (Equality 5-1) is expressed with the following two equations :
![]()

![]()
(Equality 5-3)
![]()

![]()
(Equality 5-4)
We obtain the next equation owing to (Equality 5-3).
![]()

By applying this equation to (Equality 5-4), we obtain the following equality:
![]()

![]()
(Equality 5-5)
Moreover, by substituting
for
of (Equality 5-2), we obtain the next equality :
![]()

![]()
(Equality 5-6)
(equality 5-1) and (Equality 5-2)
(Equality 5-6) are the answers for the question how a stationary object observed by the 0th observer is observed by the 1st observer traveling with linear uniform motion at a speed of
relative to the 0th observer.
Well, I ask you as follows :



is time intervals of the 1st observer observing multiple objects traveling with linear uniform motion in various directions and at various speeds. 

is time intervals of the 0th observer observing only stationary objects. Which time is absolute? In other words, which time acts as paramater to rotate hands of a clock?
The answer is
time of the 1st observer.
It is natural that an observer in the center of his/her own world observes and recognizes many movenents of surrounding objects. ( In a religious world, to the contrary, an observer may be observed by a creator or an admired Deity in the center of the world. ) Therefore, time of the 1st observer is absolute, and it is a parameter for movements of all objects. On the other hand, time of the 0th observer is relative.
To understand this statement, please see Figure 0501. This figure shows (Equality 5-6).
is the distance of the space-time point with coordinates of
from the coordinate origin.

Please see Figure 0502. We see that there are many combinations of
and
which make (Equality 5-6) valied.

When an object keeps still with respect to an observer, it is 

, and the movement of the object is expressed with a vector just on to - axis.


of (Equality 5-6) :
is called generally 'proper time.' Since it sounds like objective and absolute, I call it 'relative-time.' And I call 

'absolute-time.'

of (Equality 5-3) or 

of (Equality 5-6).

. I show it again :
) and which vertical axis is the absolute-time of the 0th observer (
).
The 1st observer is the main character of the observation.
It consists of three-dimensional space and one-dimensional
At a superficial level, its coordinate system contain both the 1st
All objects are constantly moving in this four-dimensional
I will show the example of Epstein's space-time. To be simple, we consider space as one-dimension. The object A and the object B can change velocity at a moment. They travel or stand still with always the same velocity.
Space-time points on which they exist at the start of the observation are as follows :
The object A :![]()

The object B :![]()

They travel in the positive direction at a speed of 60% of a light speed in the first
, and then they stand still in the next
, and then they travel in the positive direction at a light speed in the last
. Space-time points on which they exist at the end of the observation are as follows :
The object A :![]()

The object B :![]()

The traveling of them is shown with Epstein's space-time in Figure 0601.
Figure 0601
![]()

Length of the locus of an object shows absolute-time intervals in Epstein's space-time. We need space coordinate and absolute-time point to find the realistic space-time point on which an object exist, but we don't need relative-time point. In this sense, Epstein's four-dimensional space-time is a virtual space-time.
and
. The time coordinates of space-time points on which they exist are always the same. With respect to X-coordinate and Y-coordinate of the 'space velocity' of an object, the sum of X-coordinate to the second power and Y-coordinate to the second power is equal or under
. Please imagine the collision of these objects. It is the very collision in the elevator. That is, X-axis space coordinates, Y-axis space coordinates, and time-coordinates of space-time points on which they exist are the all same, respectively.
. Even if an object changes 'space velocity', it does not change 'space-time speed.' With respect to X-coordinate, Y-coordinate, and relative-time coordinate of the 'space-time velocity' of an object, the sum of X-coordinate to the second power, Y-coordinate to the second power, and relative-time coordinate to the second power is always equal to
. Please imagine the collision of these objects. They collide when X-axis space coordinates and Y-axis space coordinates of space-time points on which they exist are the all same, respectively, regardless of difference of relative-time coordinates of space-time points on which they exist.
with respect to Mr. A. The coordinate conversion from Mr. A's coordinate system to Mis. B's coordinate system is shown as follows :


and
, this expression takes a value of imaginary number. The area of apace-time points, on which an object, which passes the space-time origin, can exist, is inside of light cone in the Minkowski four-dimensional space-time. The area of inside of the light cone is called 'area of time like.' In this area, it is 

. The area of outside of the light cone is called 'area of space like.'
.
be the space-time point on which the photon exists at the start of the observation.
be the space-time point on which the photon exists at the end of the observation.

(Equality 6-1)
and
in Mr. A's coordinate system are converted to Mis. B's coordinate system to be as follows, respectively :

and
are as follows :
and the space-time point
as follows :





(Equality 6-2)
Lorentz transformation makes principle of relativity hold good to electromagnetic field. Plus, it shows the change of traveling of electromagnetic wave in two coordinate systems. It never shows, however, the change of traveling of an object in two coordinate systems. But, Lorentz transformation is used as such tool to produce a lot of contradictions.
. Therefore, the idea struck my mind; the idea is as follow :
Lorentz transformation comes from the principle of relativity on relationship between electric field and magnetic field, i.e. Maxwell equations. Space point
and time point
in Maxwell equations are not optional, and their relationship is shown as
.

of this equality as 'relative time' through which the photon travels; actually photon does not travel through relative time. Moreover, we consider an object travels through relative time. Let
be relative time intervals. We suppose that the following equality is satisfied :

Please imagine ; you are observing that a ball goes straight away at a speed of
, and your friend traveling with linear uniform motion at a speed of
in the opposite direction of the ball relative to you. How does your friend observe the movement of the ball? I described in Chapter 1 that Figure 0103 is wrong.
Now, I will show the correct answer. We repeat coordinate coversion expressed with (Equality 5-1) twice under the condition of 

. Then, we see how the 2nd observer observes an object observed by the 0th observer. In other words, we see how the 2nd observer observes an object observed by the 1st observer.
Let
be a speed of the 1st observer relative to the 0th observer.
Let
be a speed of the 2nd observer relative to the 1st observer.
Let
be a speed of the object observed by the 2nd observer.


By dividing
by
, we obtain
as follows :
![]()

![]()
(Equality 7-1)


with repsect to all observers.
.
rightly as follows:
The speed of photon emitted from a stationary light source is
. Plus, composition of speeds follows (Equality 7-1). Therefore, the speed of photon emitted from a light source is
regardless of a velocity of the light source.
as follows:
On the one hand, a bullet is shot from a traveling point, on the other hand, photon is emitted from a stationary space-time point on a coordinate system of an observer.
The form of a traveling of an object is different from the form of a traveling of light. Therefore, Lorentz transformation does not apply to a traveling of an object. Because, it comes from 'Vibration of photon on electromagnetic field' and 'Traveling of photon with proper speed'; Behavior of photon is 'Vibration on electromagnetic field', 'Vibration on electromagnetic wave', 'Traveling with proper speed', and 'Character as quantum.'
I must admit there is a certain logic in what you say. If we remodel Lorentz transformation, that is, we get absolute time back, we can unify the form of a traveling of photon and the form of a traveling of an object.
, we can say as follows :
:
with respect to an observer standing still with respect to ether.
:
with respect to ether, the speed of light traveling in this direction is
.
with respect to a stationary observer, as medium at a speed of
in the opposite direction.
:
with respect to ether for Mr. A standing still with respect to ether is
.
, and the speed of Ms. B with respect to Mr. A is
.
and
are the same. A speed for an objective observer and a speed for a subjective observer are the same in Newtonian mechanics.
:
with respect to all observers.
:
with respect to an observer traveling at a speed of
with respect to the light source.
:
.
is a speed of the third party. It is unnecessary and harmful in the theory of relativity. A speed of the third party is just a speed in a vision which makes the theory of relativity be confused.
A monster says:
When an object B is thrown out from a traveling object A in the perpendicular direction to the movement of the object A , whether the object A is approaching an observer or going away from the observer, the perpendicular speed of the object B relative to the observer gets slower than the speed observed by another observer moving with the same velocity as the object A . In short, vertical time of an object traveling in the horizontal direction passes more slowly than that of a stationary object.
So, let us ask the Monster the following question:
We can not understand that only vertical time passes slower, because time is one-dimension. How about thinking that vertical space is extended? We think the result is the same as your view.
Just then he says :
Ha-ha, foolish human beings! Your view fits into the trap. Listen to me carefully. Imagine that two rings of the same size are approaching face to face at high speed in the horizontal direction, and then they collid under your very nose. If this situation is observed by the other observer moving at the same velocity as the right ring, the left ring passes through the outside of the right ring without collision. If this situation is observed by the other observer moving at the same velocity as the left ring, the right ring passes through the outside of the left ring without collision. Have you noticed? You always label everthing 'good' or 'bad' selfishly, but everything is originally
.
'Law of relative vertical speed.'
with respect to the 1st observer. The object A passes through space-time origin of the 1st observer's coordinate system. The object A is traveling in the direction of Y-axis. Let
be the position of the object A at a time point of 
. We obtain the following equation :

with respect to the 1st observer in the direction of X-axis. Space-time origins of them are identical. We consider that the movement of the object A with respect to the 2nd observer is expressed with following equations :

is expressed with
and
.





is expressed as follows :
and
, it is
.
or
, it is
.
A coordinate conversion from ' the coordinate system of the 1st observer traveling at a speed of
relative to the 0th observer ' to ' the coordinate system of the 2nd observer traveling at a speed of
relative to the 1st observer in the opposite direction to the movement direction of the 0th observer relative to the 1st observer '







A coordinate conversion from ' the coordinate system of the 1st observer traveling at a speed of
relative to the 0th observer ' to ' the coordinate system of the 2nd observer traveling at a speed of
relative to the 1st observer in the perpendicular direction to the movement direction of the 0th observer relative to the 1st observer '






: The locus vector of light emitted from the light source A
: The locus vector of light emitted from the light source B
: The locus vector of the light source A
: The locus vector of the light source B
: The locus vector of the 1st observer
relative to the 1st observer observes this situation.
, the point
, and the point
owing to the 'diterminant of Lorentz transformation.'


: The locus vector of light

: The locus vector of light

: The locus vector of the 1st observer
simultaneously.


Two flashes, which came from both end of the train, are shot simultaneously with respect to me, because they are shot at the same distance away from me and they reach me at the same time. Like this, two flashes seem to be shot simultaneously with respect to her. My objective observation, however, denies this. I show the reason as follows 
In my coordinate system, a flash from a light source on the front of the train and a flash from a light source on the back of the train are shot simultaneously. They reach me at the same time.
In my coordinate system, 'the space intervals between the space point on which the flash from the light source on the front of the train is shot and the space point on which the flash reached her' are shorter than 'the space intervals between the space point on which the flash from the light source on the back of the train is shot and the space point on which the flash reached her.'
Owing to
and
, in my coordinate system, she collides with two flashes at a different time point, i.e. at separate time.
In her coordinate system, she collides with two flashes at a different time point, i.e. at separate time, because state of action of an object and situation of collision etc. are constant regardless of coordinate conversions.
Both in my coordinate system and in her coordinate system, 'the space intervals between the space point on which the light source on the front of the train exists and the space point on which she exists' are always the same length as 'the space intervals between the space point on which the light source on the back of the train exists and the space point on which she exists.'
In her coordinate system, the space point on which a flash is shot is the same as the space point on which a light source exists.
Therefore, in her coordinate system, 'the space intervals between the space point on which the flash from the light source on the front of the train is shot and the space point on which the flash reached her' are the same length as 'the space intervals between the space point on which the flash from the light source on the back of the train is shot and the space point on which the flash reached her.'
Owing to
and
, in her coordinate system, a flash from a light source on the front of the train and a flash from a light source on the back of the train are shot at a separate time. 
relativity of simultaneity of two events on different space points
.
For the man on the platform, the value of time intervals while the light emitted from the front of the train reaches the woman on the train is smaller than the value of the space intervals of the half of the train. ( Proviso : We use the 
system of units.
) That is,
with respect to the woman on the train, the light emitted from the front of the train reaches herself through the space intervals of the same value as the space intervals of the half of the train, while spending time intervals of the smaller value than the value of the space intervals of the half of the train.
Therefore, 'principle of constancy of ligth velocity' is a serious mistake. Because, with respect to the woman on the train, the light travels at a speed of more than
.
The collaboration of the speed of light and the speed of the train makes the value of the speed of light with respect to the woman on the train more than
.
.
Just because it is
With respect to the man on the platform, the light reaches the woman on the train at a speed of
through the space intervals of the smaller value than the value of the space intervals of the half of the train, while spending time intervals of the smaller value than the value of the space intervals of the half of the train.
, it is not necessarily
With respect to the woman on the train, the light reaches her through the space intervals of the same value as the space intervals of the half of the train, while spending time intervals of the smaller value than the value of the space intervals of the half of the train.

Time intervals while light trravels belongs to the coordinate system of the the man on the platform, in spite of the declaration of
with respect to the woman on the train
. If we try to find the contents of the observation of the person on the train, we must use the coordinate system of the person on the train.




We must observe from a viewpoint of a person concerned, because we can not observe in detail from a viewpoint of a third party.
The speed of the flash from the light source on the front of the train which reaches the 2nd observer with respect to the 2nd observer :
The speed of the flash from the light source on the front of the train which reaches the 1st observer with respect to the 2nd observer :
The speed of the flash from a light source on the back of the train which reaches the 2nd observer with respect to the 2nd observer :
The speed of the flash from a light source on the back of the train which reaches the 1st observer with respect to the 2nd observer :
, regardless of observers traveling with various velocities with respect to a light source. Therefore, two lights emitted simultaneously at the same distance away from a stationary observer reach the observer at the same time without fail. So, if an observer sees simultaneously two lights emitted at the same distance away from the observer in the observer's coordinate system in which the observer stands still, we see that two lights were emitted simultaneously with respect to the observer. However, if we think about the case that the 2nd observer observes the 1st observer observing the light, it is not so.
It is
the condition for an observer to observe that another person brinks at the same time as the observer brinks
that another person with the distance from the observer of
brinks
earlier than the observer brinks. 
. When the woman observes this situation, she thinks as follows to fit into a maze 
It is right that the man found simultaneously that two clocks indicate
as he says.
But, on my observation as Figure 0902, both of two clocks did not flash at
. Two flashes do not reach me simultaneously. The flash, which reached me first, flashed before
. Therefore, the clock is fast. The flash, which reached me second, flashed after
. Therefore, the clock is slow. It is the 'relativity of simultaneity.'
Oh! Calm down! Let's look at things from a different angle. The difference of the observation between the 1st observer and the 2nd observer, i.e. me, is only the speed of the train. I am the 1st observer at the same time. Therefore, my observation is the same as Figure 0901 except for the speeds of clocks, isn't it?
The 1st observer traveling with respect to me stands still with respect to himself. So, let us place the figure, in which the 1st observer stands still, on the figure, in which the 2nd observer, i.e. me, stands still. Then, speeds of the train are different. And, two clocks flash simultaneously with respect to both of us, and then two flashes, which have correct information that the clock flashed at
, reach us at
simultaneously, because light travels at a constant speed in all inertial frame of reference, regardless of the speed of light source.






and the magnitude of
are
.